Unit 9 check
Unit 9 check: Thermodynamics and Electrochemistry
11 questions from 11 lessons in Unit 9. Answer each one, and if you miss, follow the link back to where it is taught, then try again. Your score counts first tries.
Question 1 · from 9.1 · Rank it
Each sample is 1.0 mol of water. Rank the samples by their entropy.
Highest entropy first
Give each one a place, 1 for first. Give two the same place if they are equal.
Your ranking: none yet
Question 2 · from 9.2 · Calculate
Calculate ΔS° for N₂(g) + 3H₂(g) → 2NH₃(g), in J/(mol·K), with its sign. The standard molar entropies are N₂(g) 191.6, H₂(g) 130.7 and NH₃(g) 192.8 J/(mol·K). Give your answer to one decimal place.
Question 3 · from 9.3 · Calculate
For N₂(g) + 3H₂(g) → 2NH₃(g) at 298 K, ΔH° = −92.2 kJ/mol and ΔS° = −198.1 J/(mol·K). What is ΔG°, in kJ/mol? Give your answer to one decimal place.
Setup for question 4
A chemist sorts what she sees in four situations at 25 °C. In each, ΔG° tells whether the process is favored, and the observation tells whether it occurs at a measurable rate.
One of the favored changes is a mixture of hydrogen and oxygen in a sealed flask at 25 °C, where 2H₂(g) + O₂(g) → 2H₂O(l) has ΔG° = −474.2 kJ/mol. The flask shows no change over a year.
Question 4 · from 9.4 · Sort it
Tap each situation, then the bin that describes it.
Favored and occurring
Favored but under kinetic control
Not favored
Setup for question 5
Reactions in the body run at about 310 K, not 298 K. One step in a metabolic pathway has ΔG° = +7.50 kJ/mol at 310 K. These numbers are a teaching example.
Question 5 · from 9.5 · Sort it
Each card gives ΔG° for a reaction at 298 K, where RT is about 2.5 kJ/mol. Tap a card, then the bin that describes K.
K is much less than 1
K is close to 1
K is much greater than 1
Setup for question 6
A student compares three salts, each made of one cation and one anion, at 298 K. Salt Z is a made-up salt. These numbers are a teaching example. Use R = 8.314 J/(mol·K).
| Salt | ΔH° (kJ/mol) | ΔS° (J/(mol·K)) |
|---|---|---|
| NaCl | +3.9 | +43.4 |
| AgBr | +84.4 | +47.7 |
| Salt Z | −12.0 | −30.0 |
Question 6 · from 9.6 · Calculate
Using the table: what is ΔG° for dissolving salt Z at 298 K, in kJ/mol? Give your answer to the nearest 0.1 kJ/mol, with its sign.
Setup for question 7
A student studies three reactions in a model cell. Reaction 3 shares no species with the other two. These numbers are a teaching example.
| Reaction | Equation | ΔG° (kJ/mol) |
|---|---|---|
| 1 | Y + HPO₄²⁻ → Y-P + H₂O | +22.0 |
| 2 | ATP + H₂O → ADP + HPO₄²⁻ | −30.5 |
| 3 | S → T + U | −45.0 |
Question 7 · from 9.7 · Multiple choice
Using the table: which statement about the reactions is supported?
Setup for question 8
A student builds a cell from a lead electrode in 1.0 M Pb(NO₃)₂(aq) and a silver electrode in 1.0 M AgNO₃(aq). A wire with a voltmeter joins the electrodes, and a salt bridge of KNO₃(aq) joins the solutions. The voltmeter shows a steady reading while the cell runs for 30 minutes. The student weighs each electrode before and after. These numbers are a teaching example.
| Electrode | Mass before (g) | Mass after (g) | Change (g) |
|---|---|---|---|
| Lead | 12.450 | 11.820 | −0.630 |
| Silver | 9.800 | 10.456 | +0.656 |
Question 8 · from 9.8 · Decide and justify
Using the table: in the wire, which way do the electrons travel?
Which reason supports your decision?
Setup for question 9
A student has the four standard half-cells in the table. Each is at standard conditions. In every cell the student builds, the half-reaction with the more positive potential is the one reduced.
| Reduction half-reaction | E°red (V) |
|---|---|
| Ag⁺(aq) + e⁻ → Ag(s) | +0.80 |
| Cu²⁺(aq) + 2e⁻ → Cu(s) | +0.34 |
| Fe²⁺(aq) + 2e⁻ → Fe(s) | −0.44 |
| Mg²⁺(aq) + 2e⁻ → Mg(s) | −2.37 |
Question 9 · from 9.9 · Select all
Using the table: select the three true statements about the reaction Fe(s) + Mg²⁺(aq) → Fe²⁺(aq) + Mg(s) at standard conditions.
Select 3 answers, then check.
Question 10 · from 9.10 · Match
Match each value of Q to what it means for the cell potential, E, compared with E°. Every cell has a positive E° as written, so K is greater than 1.
Question 11 · from 9.11 · Fill the statement
Complete the pathway from a mass of metal to the charge that was needed.
Moles of metal = mass ÷ . Moles of electrons = moles of metal × . Charge = moles of electrons × .
0 of 11 answered.