Practice
Newton’s second law, friction and ramps
Net force and acceleration on level floors, ramps and a cart pulled by a hanging block, with kinetic and static friction.
The skill
Start with a free-body diagram, choose the system and a positive direction, add the force components along that direction to get , and divide by . On a ramp, tilt your axes so one runs along the incline; the weight then splits into along the ramp and into it. Kinetic friction is , while static friction takes whatever value keeps the surfaces from sliding, up to . Students most often write on a ramp, where the normal force balances only the perpendicular part of the weight.
A worked example
A 0.60 kg block slides down a frictionless ramp inclined at 30° above the horizontal. Use g = 10 m/s².
What is the magnitude of the block's acceleration, in m/s²? Give your answer to three significant figures.
Solution
- Only two forces act: the weight mg straight down and the normal force perpendicular to the ramp. The normal force has no component along the ramp.
- The component of the weight along the ramp is mg sin 30°, so = (mg sin 30°) ÷ m = 10 sin 30° = 5.00 m/s².
- The mass cancels, so a heavier block on the same ramp has the same acceleration.
Answer: 5