Practice

Newton’s second law, friction and ramps

Net force and acceleration on level floors, ramps and a cart pulled by a hanging block, with kinetic and static friction.

The skill

Start with a free-body diagram, choose the system and a positive direction, add the force components along that direction to get Fnet, and divide by msys. On a ramp, tilt your axes so one runs along the incline; the weight then splits into mgsin⁡θ along the ramp and mgcos⁡θ into it. Kinetic friction is μkFn, while static friction takes whatever value keeps the surfaces from sliding, up to μsFn. Students most often write Fn=mg on a ramp, where the normal force balances only the perpendicular part of the weight.

A worked example

A 0.60 kg block slides down a frictionless ramp inclined at 30° above the horizontal. Use g = 10 m/s².

What is the magnitude of the block's acceleration, in m/s²? Give your answer to three significant figures.

Solution

  1. Only two forces act: the weight mg straight down and the normal force perpendicular to the ramp. The normal force has no component along the ramp.
  2. The component of the weight along the ramp is mg sin 30°, so asys=Fnet/msys = (mg sin 30°) ÷ m = 10 sin 30° = 5.00 m/s².
  3. The mass cancels, so a heavier block on the same ramp has the same acceleration.

Answer: 5

Your turn

Lessons behind these problems